Answer by Ramakrishna S for There are $n$ urns with $4$ white and $6$ black...
Given that there are total $n+1$ bags of which first $n$ bags contain $4W + 6B$First we find the total probability of drawing $2$ black balls. Probability of choosing each of the first $n$ bags =...
View ArticleAnswer by Adriano for There are $n$ urns with $4$ white and $6$ black balls.
Define the events:$A =$ the last urn is chosen (and not one of the first $n$ urns).$B =$ the two balls drawn from the chosen urn are both black.Then by Bayes' Rule, we have:$$\frac{1}{7} = \Pr[A \mid...
View ArticleThere are $n$ urns with $4$ white and $6$ black balls.
There are n urns marked $1, 2, ..., n$ respectively, with each of the $n$ urns containing 4 white and 6 black balls. There is another urn, marked $(n+1)$ containing $5$ white and $5$ black balls. An...
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